Question

If the potential difference across the positive and negative terminals of the battery is 2 V, what is the current (in amps) flowing through R₁?

Round to the nearest thousandth.

R₁ = 79 Ω
R₂ = 87 Ω

Please show work!!!!

Answer 1

We need to use Ohm's law to calculate the current flowing through R₁:

I = V / R₁

where I is the current in amps, V is the potential difference in volts, and R₁ is the resistance in ohms.

Substituting the given values, we get:

I = 2 V / 79 Ω

I ≈ 0.0253 A

Therefore, the current flowing through R₁ is approximately 0.0253 amps.