Question

What is the time constant, in terms of R and C , for the charging circuit if the two capacitors are in series

Answer 1

If two capacitors C1 and C2 are in series with a resistance R, the equivalent capacitance of the circuit is:

1/Ceq = 1/C1 + 1/C2

The time constant for charging the circuit is given by:

τ = R * Ceq

Substituting the value of Ceq in terms of C1 and C2, we get:

τ = R * (C1 * C2) / (C1 + C2)

Therefore, the time constant for the charging circuit with two capacitors in series is R times the product of the two capacitances divided by their sum.