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If $\sqrt[3]{6}\cdot\sqrt[3]{-21}\cdot\sqrt[3]{33}$ in simplified form is $a\sqrt[3]{b}$, where $a$ and $b$ are integers and $b>0$, then what is $a b$

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Final answer:

To simplify the expression √3(6)•√3(-21)•√3(33), we can combine the cube roots and simplify the numbers inside. The simplified form is -12√3(1).

Step-by-step explanation:

To simplify the expression √3(6)•√3(-21)•√3(33), we can combine the cube roots and simplify the numbers inside. √3(6)•√3(-21)•√3(33) = √3(6•-21•33). Then, we can simplify the product inside the cube root: √3(6•-21•33) = √3(-2736). Since the cube root of -2736 is -12, the expression simplifies to -12√3(1).

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