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The half-life for the radioactive decay of c-14 is 5730 years and is independent of the initial concentration. if a sample of c-14 initially contains 2.70 x 10^19 atoms, how many atoms does it contain after 2018 years?

User SIDU
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Answer: 1.64 x 10^19 atoms

Step-by-step explanation:

After 2018 years, the sample of c-14 will contain 1.64 x 10^19 atoms. This is calculated by using the equation A = A0 * e^(-k * t), where A is the amount of atoms present after a certain amount of time, A0 is the initial amount of atoms, k is the radioactive decay constant, and t is the amount of time that has passed. Plugging in the values, we have 1.64 x 10^19 = 2.70 x 10^19 * e^(-0.00012 * 2018). Therefore, after 2018 years, the sample of c-14 will contain 1.64 x 10^19 atoms.

User Ssssteffff
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