Question

Iron has a specific heat of o.45 J/g °C. Removing -1.16 E 2 J of energy lowered the temperature of iron from 89 °C to 26.41 °C. What was the mass of the iron?

Answer 1

m = 4.11 grams

Step-by-step explanation:

Given that,

The specific heat of Iron, c = 0.45 J/g°C

Heat removed,
`Q=1.16* 10^2\ J`

Initial temperature,
`T_i=89^(\circ) C`

Final temperature,
`T_f=26.41^(\circ) C`

We need to find the mass of the iron. We know that the heat removed in terms of specific heat is given by :

`Q=mc\Delta T\\\\m=(Q)/(c\Delta T)\\\\m=(-1.16* 10^2)/(0.45* (26.41-89))\\\\m=4.11\ g`

So, the mass of the iron is 4.11 grams.