Answer:
20.23grams
Explanations
Given the chemical equation below;
Determine the mole of AlCl3
Mole = Mass/molar mass
mole of AlCl3 = 100/133.34
Mole of AlCl3 = 0.749moles
According to stoichiometry, 2 moles of AlCl3 produced 2 moles of Al, hence the mole of Al required is 0.749moles
Determine the mass of Al
Mass of Al = 0.749 * 26.98
Mass of Al = 20.23grams
Hence the mass of Al that can be produced is 20.23grams