Answer:
14
Explanation:
Let the first term be T¹
Let the second term be T²
Therefore T¹ = -2
T²= 2
The common difference d = T²–T¹
2–(-2)
= 4
You can also confirm this with the second and third terms.
The next term after 10 will be gotten by adding the common difference to 10
which is 10+4=14
OR
The next term is the 5th
T⁵= a + 4d
a= -2, d= 4
T⁵= -2 + 4{4}
T⁵= -2 + 16
T⁵= 14