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2x(x+3) = x -4
ive been stuck on this for a while

1 Answer

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To solve the equation 2x(x+3) = x -4, we need to first simplify the left-hand side of the equation by multiplying out the brackets:

2x(x+3) = 2x^2 + 6x

Now, we can rewrite the equation as:

2x^2 + 6x = x - 4

To solve for x, we need to bring all the terms to one side of the equation. Let's start by subtracting x and adding 4 to both sides:

2x^2 + 5x + 4 = 0

Now, we can factor this quadratic equation. To do this, we need to find two numbers that multiply to give 8 and add to give 5. These numbers are 1 and 4. So, we can rewrite the equation as:

(2x + 1)(x + 4) = 0

This means that either 2x + 1 = 0 or x + 4 = 0.

Solving for 2x + 1 = 0, we get:

2x + 1 = 0

2x = -1

x = -1/2

Solving for x + 4 = 0, we get:

x + 4 = 0

x = -4

Therefore, the solutions to the equation 2x(x+3) = x -4 are x = -1/2 and x = -4
User Ronny Shibley
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