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Write an equation of the line that passes through the given points.

(-1,5) and (2, -1)
The equation is y= . (Type your answer in slope-intercept form.)

User Ephtron
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1 Answer

5 votes

Answer:

the equation of the line is: y = -2x + 3

Explanation:

To find the equation of the line that passes through the points (-1, 5) and (2, -1), we can use the slope-intercept form of a line, which is:

y = mx + b

where m is the slope of the line, and b is the y-intercept.

To find the slope, we can use the formula:

m = (y2 - y1) / (x2 - x1)

where (x1, y1) and (x2, y2) are the coordinates of the two points.

Plugging in the given values, we get:

m = (-1 - 5) / (2 - (-1)) = -6 / 3 = -2

So the slope of the line is -2.

To find the y-intercept, we can plug in one of the points and the slope into the slope-intercept form of the line and solve for b.

Let's use the point (-1, 5):

y = mx + b

5 = (-2)(-1) + b

5 = 2 + b

b = 3

So the y-intercept is 3.

Putting it all together, the equation of the line is:

y = -2x + 3

User Aman Singh Rajpoot
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