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What is the resistivity of a wire of 0.91 mm diameter, 2.7 m length, and 70 mω resistance.

User SanketR
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1 Answer

5 votes

Answer:

the resistivity of the wire is 1.70 x 10^-7 Ωm.

Step-by-step explanation:

The resistivity of a wire can be calculated using the formula:

ρ = (RA)/L

where ρ is the resistivity of the wire, R is the resistance of the wire, A is the cross-sectional area of the wire, and L is the length of the wire.

To find the cross-sectional area of the wire, we first need to calculate the radius:

r = d/2 = 0.91 mm / 2 = 0.455 mm = 4.55 x 10^-4 m

where d is the diameter of the wire.

The cross-sectional area is then:

A = πr^2 = π(4.55 x 10^-4 m)^2 = 6.53 x 10^-7 m^2

Now we can plug in the values for R, A, and L:

ρ = (RA)/L = (70 mΩ x 6.53 x 10^-7 m^2) / 2.7 m = 1.70 x 10^-7 Ωm

Therefore, the resistivity of the wire is 1.70 x 10^-7 Ωm.

User Rostyslav Diachok
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