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At which value will the graph of y = cot x have a zero​

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y = cot x have zero for value of x = nπ + π/2

What are trigonometric ratio ?

In trigonometry, there are six trigonometric ratios, namely, sine, cosine, tangent, secant, cosecant, and cotangent. These ratios are written as sin, cos, tan, sec, cosec(or csc), and cot in short.

Given equation,

y = cot x

It is given that cot x = 0

hence,

cot is zero in the first and the third quadrants.

cot π/2 = 0.

In the first quadrant, x = π/2

In the third quadrant, x = π + π/2 as cot 3π/2 = 0

Thus, the principle solutions are: x = π/2, and 3π/2.

Now,

cot x = cot π/2

Therefore, x = nπ + π/2, where n ∈ Z is the general solution.

Hence, for value of x = nπ + π/2, graph of y = cot x have a zero.

User Yan Khonski
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