Answer: To calculate the amount of heat absorbed by the water, you need to use the formula:
Q = mcΔT
where Q is the amount of heat absorbed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
Assuming that the density of water is 1 g/mL and its specific heat capacity is 4.184 J/(g·K), the mass of 1.00 L of water is:
m = (1.00 L)(1000 mL/L)(1 g/mL) = 1000 g
The change in temperature is:
ΔT = 85°C - 18°C = 67°C
Now we can plug in these values to find the amount of heat absorbed by the water:
Q = mcΔT
Q = (1000 g)(4.184 J/g·K)(67°C)
Q = 281096 J
Therefore, when 1.00 L of water is heated from 18°C to 85°C, it absorbs approximately 281096 J of heat.
Step-by-step explanation: