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If a ray of light travels 3 x 108 m/sec for 6.9 x 1013 sec, how far did it

travel?
A. 20.7 x 1021
B. 2.07 x 1022
C. 2.07 x 10-5
D. 2.07 x 105

1 Answer

3 votes

Answer:

the ray of light traveled a distance of 2.07 x 10^22 meters. The answer is option B, 2.07 x 10^22.

Explanation:

We can use the formula:

Distance = Speed x Time

where the Speed is 3 x 10^8 m/sec, and the Time is 6.9 x 10^13 sec.

Distance = (3 x 10^8 m/sec) x (6.9 x 10^13 sec)

Distance = 2.07 x 10^22 meters

Therefore, the ray of light traveled a distance of 2.07 x 10^22 meters. The answer is option B, 2.07 x 10^22.

User Orr Matarasso
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