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If s^2=t^-1 and t^1/4=u^-1/3, what is the value of s interm of u

User Tibi
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1 Answer

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Starting with the given equations:

s^2 = t^-1

t^(1/4) = u^(-1/3)

First, we can simplify the second equation by raising both sides to the 4th power:

t^(1/4)^4 = u^(-1/3)^4

t = u^(-4/3)

Substitute this value for t in the first equation:

s^2 = (u^(-4/3))^-1

s^2 = u^(4/3)

Taking the square root of both sides:

s = ± u^(2/3)

Therefore, the value of s in terms of u is s = ± u^(2/3).

User Gefilte Fish
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