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A tank in the shape of a hemisphere has a diameter of 22 feet. If the liquid that fills the tank has a density of 66.5 pounds per cubic foot, what is the total weight of the liquid in the tank, to the nearest full pound?

User Kevin Liu
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Answer:

The first step to solve this problem is to find the volume of the hemisphere-shaped tank. We know that the diameter of the tank is 22 feet, so the radius is half of that, which is 11 feet. The volume of a hemisphere can be calculated using the formula:

V = (2/3)πr^3

Plugging in the values, we get:

V = (2/3)π(11)^3 ≈ 5,954.6 cubic feet

Next, we need to find the weight of the liquid in the tank. We know that the density of the liquid is 66.5 pounds per cubic foot, so the weight of the liquid can be calculated by multiplying the volume of the liquid by its density:

Weight = volume x density = 5,954.6 cubic feet x 66.5 pounds/cubic foot ≈ 396,270.7 pounds

Rounding this to the nearest full pound gives us:

Weight ≈ 396,271 pounds

Therefore, the total weight of the liquid in the tank is approximately 396,271 pounds.

Explanation:

User Serbin
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