To calculate the heating load for the wall, we need to determine the overall thermal resistance (R-value) of the wall and the surface area of the insulated and framed portions of the wall. We can then use the formula:
Heat Load = U x A x TD
where U is the overall heat transfer coefficient (the reciprocal of R-value), A is the surface area, and TD is the temperature difference.
Using Table 3.2, we can find the R-values for each layer of the wall:
Face brick: R = 0.44
Air space: R = 1.00
Plywood sheathing: R = 0.94
Wood studs with R13 batt insulation: R = 14.13 (80% insulated area)
Drywall: R = 0.45
The overall R-value for the wall is:
R = R_brick + R_air + R_plywood + (0.8 x R_studs) + R_drywall
R = 0.44 + 1.00 + 0.94 + (0.8 x 14.13) + 0.45
R = 23.57
So, the overall U-value is:
U = 1 / R
U = 0.0424 Btu/(h-ft^2-°F)
The surface area of the insulated portion of the wall is:
A_insulated = 8 ft x 600 ft x 0.8
A_insulated = 3,840 ft^2
The surface area of the framed portion of the wall is:
A_framed = 8 ft x 600 ft x 0.2
A_framed = 960 ft^2
The total surface area is:
A_total = A_insulated + A_framed
A_total = 4,800 ft^2
The temperature difference is given as 59°F.
Plugging in these values, we get:
Heat Load = U x A_total x TD
Heat Load = 0.0424 Btu/(h-ft^2-°F) x 4,800 ft^2 x 59°F
Heat Load = 11,975 Btu/h
Therefore, the heating load for the wall is approximately 12,000 Btu/h. None of the given answer choices match this result, so none of them are correct.