Final Answer:
To demonstrate that ( Csubseteq [a, b] ) is a subspace, it is essential to prove that the set is closed under addition and scalar multiplication.
Step-by-step explanation:
To establish ( C subseteq [a, b] ) as a subspace, it must satisfy two key conditions: closure under addition and closure under scalar multiplication.Firstly, to show closure under addition, let ( f, g in C). We need to prove that ( f + g in C ). Since ( f ) and ( g ) are continuous functions on ( [a, b] ), their sum( f + g ) is also continuous on ( [a, b] ) by the properties of continuous functions. Therefore,( C ) is closed under addition.
Secondly, for closure under scalar multiplication, let ( f in C ) and ( c ) be a scalar. We need to show that ( cf in C ). Again, as ( f ) is continuous on ( [a, b] ), the product ( cf ) is continuous as well. Thus, ( C ) is closed under scalar multiplication.In summary, by proving closure under addition and scalar multiplication, we establish that ( C subseteq [a, b] ) is a subspace. These properties are fundamental in calculus and ensure that the set ( C ) behaves as a vector subspace within the given interval ( [a, b] ).