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suppose you toss two dice at the same time. if at least one of them is 5 or 6 you win. then, you toss them 8 times; what is your expected number of wins?

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Explanation:

The probability of winning on a single toss of two dice is equal to the probability of getting at least one 5 or 6, which is 11/36. The probability of losing on a single toss is 1 - 11/36 = 25/36.

Let X be the number of wins in 8 tosses. Then X follows a binomial distribution with n=8 and p=11/36. The expected number of wins is given by:

E(X) = n * p = 8 * 11/36 = 2.44

Therefore, the expected number of wins in 8 tosses is approximately 2.44.

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