Answer:
There are approximately 1.354 x 10^25 chloride ions in 7.50 mol of aluminum chloride.
Step-by-step explanation:
The chemical formula for aluminum chloride is AlCl3, which means that each molecule of aluminum chloride contains 3 chloride ions.
To determine the number of chloride ions in 7.50 mol of aluminum chloride, we can start by calculating the number of moles of chloride ions:
Number of moles of chloride ions = Number of moles of aluminum chloride x Number of chloride ions per molecule
Number of moles of chloride ions = 7.50 mol AlCl3 x 3 mol Cl- / 1 mol AlCl3
Number of moles of chloride ions = 22.5 mol Cl-
Therefore, there are 22.5 moles of chloride ions in 7.50 mol of aluminum chloride. To convert this to the number of chloride ions, we can use Avogadro's number, which is 6.022 x 10^23 particles per mole:
Number of chloride ions = Number of moles of chloride ions x Avogadro's number
Number of chloride ions = 22.5 mol Cl- x 6.022 x 10^23 ions/mol
Number of chloride ions = 1.354 x 10^25 ions
So there are approximately 1.354 x 10^25 chloride ions in 7.50 mol of aluminum chloride.