173k views
2 votes
How many chloride ions are there in 7.50 mol of aluminum chloride?

User Ijse
by
8.1k points

1 Answer

4 votes

Answer:

There are approximately 1.354 x 10^25 chloride ions in 7.50 mol of aluminum chloride.

Step-by-step explanation:

The chemical formula for aluminum chloride is AlCl3, which means that each molecule of aluminum chloride contains 3 chloride ions.

To determine the number of chloride ions in 7.50 mol of aluminum chloride, we can start by calculating the number of moles of chloride ions:

Number of moles of chloride ions = Number of moles of aluminum chloride x Number of chloride ions per molecule

Number of moles of chloride ions = 7.50 mol AlCl3 x 3 mol Cl- / 1 mol AlCl3

Number of moles of chloride ions = 22.5 mol Cl-

Therefore, there are 22.5 moles of chloride ions in 7.50 mol of aluminum chloride. To convert this to the number of chloride ions, we can use Avogadro's number, which is 6.022 x 10^23 particles per mole:

Number of chloride ions = Number of moles of chloride ions x Avogadro's number

Number of chloride ions = 22.5 mol Cl- x 6.022 x 10^23 ions/mol

Number of chloride ions = 1.354 x 10^25 ions

So there are approximately 1.354 x 10^25 chloride ions in 7.50 mol of aluminum chloride.

User Jfalkson
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.