Question

if 150 ml of 0.055 m hno3 are needed to completely neutralize 1.48 g of an impure sample of hydrogen carbonate, what pecent of the sample is baking soda

Answer 1

This calculation involves using the moles of HNO3 needed to completely neutralize the impure sample of hydrogen carbonate. The moles of HNO3 can be calculated by dividing the volume of HNO3 (150 mL) by the molarity of HNO3 (0.055 M). The moles of hydrogen carbonate can be calculated by dividing the mass of the sample (1.48 g) by the molar mass of hydrogen carbonate (84.01 g/mol). The ratio of the moles of hydrogen carbonate to the moles of HNO3 is then used to calculate the percentage of.