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determine the equation of the parabola (simplified) with roots -3+sqrt6 and -3-sqrt6, and passing through the point (-1,4)

User Nick Burke
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1 Answer

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Given:

Roots:


\begin{gathered} -3+\sqrt[]{6} \\ -3-\sqrt[]{6} \end{gathered}

Point: (-1,4)

To determine the equation of the parabola with the given roots and point, we find the missing values first.

Since the roots are given, we can say that the equation is:


y=a(x+3-\sqrt[]{6})(x+3+\sqrt[]{6})

Next, we expand the terms.


y=a(x^2+6x+3)

Then, we plug in x= -1, and y=4 into the equation to get the value of a.


\begin{gathered} y=a(x^2+6x+3) \\ 4=a((-1)^2+6(-1)+3) \\ \text{Simplify and rearrange} \\ 4=a(-2) \\ a=(4)/(-2) \\ a=-2 \end{gathered}

So,


undefined

User Hilydrow
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