Final answer:
The column space of a 4 x 7 matrix A with three pivot columns can be represented as ℝ^3, and the dimension of Nul A is determined to be 4 by using the rank-nullity theorem.
Step-by-step explanation:
If a 4 x 7 matrix A has three pivot columns, this means that the rank of matrix A is 3. The column space of A, denoted as Col A, is the subspace of ℝ^4 spanned by the pivot columns. Since there are three pivot columns, the dimension of Col A, also known as the rank, is 3, which can be represented as ℝ^3 in terms of dimensionality. Therefore, Col A ≅ ℝ^3.
Regarding the dimension of the null space of A, also known as Nul A, the rank-nullity theorem can be applied. The theorem states that the dimension of the column space plus the dimension of the null space equals the number of columns in the matrix. In this case, we have:
- Dimension of Col A (rank) = 3
- Number of columns in A = 7
So, the dimension of Nul A = Number of columns - Rank = 7 - 3 = 4. Therefore, the dimension of Nul A is 4.