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Show all work to multiply (6+ √-64)(3-√-16).

User Moyote
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\sf(6 + √( - 64) )(3 - √( - 16) )

  • If we simplify in the set of real numbers, it will be undefined because root can never be negative...

So, We will solve it in set of imaginary numbers;


\tt(6 + 8i)(3 - 4i) \\ \tt18 - 24i + 24i + 32 \\ \tt18 + 32 = 50

User Henry Pootle
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