Answer:
10 N
Step-by-step explanation:
qual to the net change of momentum of the clay divided by the time duration of impact.
So, the force which the floor exerts on the clay is equal to the net momentum change of the clay divided by the time duration of impact. Since the clay does not rebound and the duration of impact is 0.04 s, the force which the floor exerts on the clay during the impact is equal to 0.2 kg * 2 m / 0.04 s = 10 N.
another way, if you didn't understand!!
You can use the impulse-momentum relationship to solve this problem. The impulse-momentum relationship states that the change in momentum of an object is equal to the impulse applied to it. In this case, the change in momentum of the clay is equal to the force exerted by the floor multiplied by the time of the collision. Since the clay is released from rest, the change in momentum is equal to the final momentum. Therefore, the force exerted by the floor is equal to the final momentum divided by the time of the collision:
F = mv/t
where m is the mass of the clay, v is the velocity of the clay, and t is the time of the collision.
Substituting the given values, we get:
F = (0.2 kg)(2 m/s)/(0.04 s) = 10 N
Therefore, the force exerted by the floor on the clay during the impact is 10 N.