Final answer:
To reach a total capacitance of 25.0 µF with a 75.0 µF capacitor, an implausible negative-value capacitor would theoretically be required. Hence, you cannot achieve 25.0 µF with a 75.0 µF capacitor and would need a different set of capacitors.
Step-by-step explanation:
To achieve a total capacitance of 25.0 µF using a 75.0 µF capacitor, you would need to connect an additional capacitor in series. The combined capacitance (Ctotal) of capacitors in series can be found using the formula 1/Ctotal = 1/C1 + 1/C2. Plugging in the known values, 1/25.0 µF = 1/75.0 µF + 1/C2, we can solve for C2, the value of the required additional capacitor.
First, we calculate the reciprocals: 1/25.0 µF = 0.04 µ
d 1/75.0 µF = 0.01333 µ
subtracting the reciprocal of the 75.0 µF capacitor from the total desired reciprocal gives us 0.04 µ
- 0.01333 µ
= 0.02667 µ
. To find the value of the required capacitor, C2, we take the reciprocal of this result, giving us approximately C2 = 1/0.02667 µ
≈ 37.5 µF.
However, since we started with a capacitor that was larger than needed, the additional capacitor required has a negative capacitance, which is not possible in practice. This means that you cannot achieve a total capacitance of 25.0 µF using a 75.0 µF capacitor alone; instead, you would need a different combination of capacitors.