Answer:
The particle energy of the boron nucleus is equal to the work done on it, so the particle energy is 7.4 x 10-9 J. The rest energy of the particle can be calculated by multiplying the mass of the particle (in kilograms) by the speed of light squared (Joules per kilogram), which yields a rest energy of 8.95 x 10-27 J. The kinetic energy of the particle is the difference between the particle energy and the rest energy, so it is equal to 8.94 x 10-27 J.