A car accelerates from 20.0 m/s to 28.0 m/s over a distance of 50.0 m. What is the car’s acceleration?

asked Mar 1, 2022 196k views

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Answer:

Step-by-step explanation:

V^2=V^2_o+2a(x_f-x_i)

$28^2=20^2+2a(50)\\784=400+100a\\384=100a\\a=3.84m/s^2$

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