Question

A tennis player hits a tennis ball, which leaves the

racket with an initial velocity of 44 m/s at an angle
of 37° above the horizontal. What are the horizontal
and vertical components of the tennis ball's initial
velocity?


vx=


vy=

Answer 1

We can use trigonometry to find the horizontal and vertical components of the initial velocity of the tennis ball:

The horizontal component of the initial velocity (vx) is given by:

vx = v * cos(θ)

where v is the magnitude of the initial velocity (44 m/s) and θ is the angle above the horizontal (37°). Substituting these values, we get:

vx = 44 m/s * cos(37°) ≈ 35.26 m/s

Therefore, the horizontal component of the initial velocity of the tennis ball is approximately 35.26 m/s.

The vertical component of the initial velocity (vy) is given by:

vy = v * sin(θ)

where v is the magnitude of the initial velocity (44 m/s) and θ is the angle above the horizontal (37°). Substituting these values, we get:

vy = 44 m/s * sin(37°) ≈ 26.61 m/s

Therefore, the vertical component of the initial velocity of the tennis ball is approximately 26.61 m/s