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Solve the following: 2(b + 12) + 4b = 6

User Preeze
by
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2 Answers

4 votes

b = -3

2(b + 12) + 4b = 6

step 1: multiply the 2 with (b + 12)

2b + 24 + 4b = 6

step 2: add like terms

6b + 24 = 6

step 3: subtract 24 on both sides

6b = -18

step 4: divide by 6 on both sides

b = -3

User Kokos
by
7.4k points
4 votes

Answer: b = -3

Explanation:

First you use distribution to solve 2(b+12).

2 x b = 2b and 2 x 12 = 24

So you've got 2b + 24.

Then, you put the entire equation together

2b + 24 +4b = 6

You combine like terms: 2b + 4b = 6b

So, 6b + 24 = 6

Subtract 6 - 24; since you're trying to get both the variable and number on opposite sides of each other.

Therefore, 6b/6 = -18/6; Divde 6 by both sides

That gives you b = - 3

User Yahreen
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7.3k points