200k views
2 votes
Write the equation of the line that passes through (-8, -4) and (-6, -1) in slope-intercept form.

Write the equation of the line that passes through (-8, -4) and (-6, -1) in slope-example-1
User JonyD
by
7.8k points

1 Answer

2 votes

Answer: To write the equation of a line in slope-intercept form (y = mx + b), we need to find the slope (m) and y-intercept (b) of the line.

We can use the two given points (-8, -4) and (-6, -1) to find the slope:

m = (y2 - y1) / (x2 - x1)

m = (-1 - (-4)) / (-6 - (-8))

m = 3 / 2

Now that we have the slope, we can use either of the two given points to find the y-intercept:

y = mx + b

-1 = (3/2)(-6) + b

-1 = -9 + b

b = 8

Therefore, the equation of the line in slope-intercept form is:

y = (3/2)x + 8

Explanation:

User Radouane
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories