200k views
2 votes
Write the equation of the line that passes through (-8, -4) and (-6, -1) in slope-intercept form.

Write the equation of the line that passes through (-8, -4) and (-6, -1) in slope-example-1
User JonyD
by
7.4k points

1 Answer

2 votes

Answer: To write the equation of a line in slope-intercept form (y = mx + b), we need to find the slope (m) and y-intercept (b) of the line.

We can use the two given points (-8, -4) and (-6, -1) to find the slope:

m = (y2 - y1) / (x2 - x1)

m = (-1 - (-4)) / (-6 - (-8))

m = 3 / 2

Now that we have the slope, we can use either of the two given points to find the y-intercept:

y = mx + b

-1 = (3/2)(-6) + b

-1 = -9 + b

b = 8

Therefore, the equation of the line in slope-intercept form is:

y = (3/2)x + 8

Explanation:

User Radouane
by
7.6k points