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Select the correct answer from each drop-down menu. A transversal t intersects two parallel lines a and b, forms two groups of angles. On top line a, starting from the top left, clockwise, angles are 1, 2, 3, and 4. On below line b, starting from the top left, clockwise, angles are 5, 6, 7, and 8. In the figure, a ∥ b , and both lines are intersected by transversal t. Complete the statements to prove that m∠1 = m∠5. a ∥ b (given) m∠1 + m∠3 = 180° (Linear Pair Theorem) m∠5 + m∠6 = 180° (Linear Pair Theorem) m∠1 + m∠3 = ∠5 + ∠6 () m∠3 = m∠6 () m∠1 = m∠5 (Subtraction Property of Equality)

User Dasnixon
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Answer: a ∥ b (given)

m∠1 + m∠3 = 180° (Linear Pair Theorem)

m∠5 + m∠6 = 180° (Linear Pair Theorem)

m∠1 + m∠3 = m∠5 + m∠6 (Corresponding Angles Postulate)

m∠3 = m∠6 (Subtraction Property of Equality)

m∠1 = m∠5 (Subtraction Property of Equality)

Explanation:

User Gursewak Singh
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