Answer: We can use long division to divide (b⁴ + b³ - 90b² + 6) by (b + 10):
b³ - 9b² + 90b - 900
b + 10 | b⁴ + b³ - 90b² + 6
- b⁴ - 10b³
--------------
- 9b³ - 90b²
+ 9b³ + 90b²
--------------
0b² + 6
- 0b² - 0
-------
6
Therefore, (b⁴ + b³ - 90b² + 6) ÷ (b + 10) = b³ - 9b² + 90b - 900 with a remainder of 6.
Explanation: