ements Us Question 4 A 4 in. 65° В Find the area of the sector formed by Z(ABC) in 2 Question Help: 0 Video

Gugguson asked Sep 11, 2023

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Gugguson asked Sep 11, 2023

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26 votes

Since 65 is equal to 13pi/36, then the area is:

$(4^2)((13\pi)/(36))((1)/(2))=8((13\pi)/(36))=(26\pi)/(9)=9.076in^2$

Robintw answered Sep 15, 2023

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