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There are 35 cars in a car race. The first-, second-, and third-place finishers win prizes. How many arrangements of top-three finishers are possible?

Type the correct answer in the box.

User Yeraldin
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2 Answers

0 votes

Answer: 39,690

Step-by-step explanation: The number of arrangements of the top-three finishers can be found using the permutation formula:

n P r = n! / (n - r)!

Where n is the total number of cars (35) and r is the number of cars that will finish in the top three (3).

So, the number of arrangements of top-three finishers is:

35 P 3 = 35! / (35 - 3)!

= 35! / 32!

= 35 x 34 x 33

= 39,690

Therefore, there are 39,690 possible arrangements of top-three finishers in the car race.

User Lucas Eduardo
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6.8k points
5 votes

Answer:

There are 39,270 possible arrangements of top-three finishers.

Explanation:

Edmentum

There are 35 cars in a car race. The first-, second-, and third-place finishers win-example-1
User PatL
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