Answer:
Explanation: To find the pressure of the nitrogen alone, we need to subtract the vapor pressure of water at 70°C from the total pressure. Therefore, the pressure of nitrogen alone would be:
2590 mm Hg - 233.7 mm Hg = 2356.3 mm Hg
To find the total pressure of the mixture, we simply add the partial pressures of the individual gases:
Total pressure = 5.00 atm + 4.65 atm + 3.01 atm + 121.56 kPa
= 12.53 atm
Note that we need to convert the partial pressure of the fourth gas from kPa to atm before adding it to the other partial pressures.
The total pressure in the flask is the sum of the partial pressures of each gas:
Total pressure = 460 mm Hg + 275 mm Hg + 520 mm Hg
= 1255 mm Hg
To find the partial pressure of neon, we need to subtract the vapor pressure of water at 28.0°C from the total pressure, and then subtract the partial pressure of helium from the result:
Partial pressure of neon = Total pressure - Vapor pressure of water - Partial pressure of helium
= 745 mmHg - 28.3 mmHg - 368 mmHg
= 348.7 mmHg
The partial pressure of helium can be found by subtracting the partial pressures of oxygen and nitrogen from the total pressure:
Partial pressure of helium = Total pressure - Partial pressure of oxygen - Partial pressure of nitrogen
= 6.11 atm - 1780 mmHg - 174.1 kPa
= 0.273 atm
Note that we need to convert the partial pressure of nitrogen from kPa to atm before subtracting it from the total pressure.
To find the partial pressure of oxygen, we need to subtract the vapor pressure of water at 23°C from the total pressure:
Partial pressure of oxygen = Total pressure - Vapor pressure of water
= 732.0 mmHg - 21.1 mmHg
= 710.9 mmHg