Question

Can someone help with this sat question?

Answer 1

Answer:A

Step-by-step explanation:

we can show,

`8^(x) as (2^(3))^(x) =2^(3x)\\`

and,

`(x^(a) )/(x^(b) ) =x^(a-b)`

`(2^(3x))/(2^(y) ) =2^(3x-y)\\ we \ know \ that,\\3x-y=12,\\then,\\2^(3x-y) =2^(12)`

Answer 2

Step-by-step explanation:

To solve this problem, we need to first rearrange the given equation so that we can solve for one of the variables in terms of the other. We can rearrange 3x - y = 12 to get y = 3x - 12.

Now, we can substitute 3x - 12 for y in the expression 8^x/2^y:

8^x/2^y = 8^x/2^(3x-12)

Next, we can simplify the expression by using exponent rules to rewrite 8 and 2 as powers of 2:

8^x = (2^3)^x = 2^(3x)

2^(3x-12) = 2^(-12) * 2^(3x) = 1/2^12 * 2^(3x)

Substituting these expressions into the original equation, we get:

8^x/2^y = 2^(3x)/(1/2^12 * 2^(3x))

Simplifying the denominator by multiplying the numerator and denominator by 2^12, we get:

8^x/2^y = 2^(3x) * 2^12

Combining the exponents, we get:

8^x/2^y = 2^(3x + 12)

Therefore, the value of 8^x/2^y is 2^(3x + 12) for the given equation 3x - y = 12.