For the given problem:
Let the speed of the airplane in still air = x
And the speed of the wind = y
when the airplane flies into a headwind for 10 hours Covering a distance of 2000 miles.
So, speed = distance over time
so,
When the airplane has a tailwind and covers the same distance in 8 hours
so,
Solve the equations (1) and (2)
Add the equation to cross y, then solve for x:
substitute with x into equation (2) to find y
So, the answer will be:
The speed of the plane in still air = 225 miles per hour
The speed of the wind = 25 miles per hour