Question

Identify the oxidizing agent in the reaction: 8h (aq) 6cl−(aq) sn(s) 4no3−(aq) → sncl62−(aq) 4no2(g) 4h2o(l)

Answer 1

Answer: Sn (s)

Step-by-step explanation:

Oxidation is losing electrons and Sn(s) charge is zero and Sn in the SnCl -2 ion is +4 so it lost 4 electrons