Answer:
201,216 J
Step-by-step explanation:
To calculate the heat that must be removed from 600 g of water at 80ºC to bring it down to 0ºC, we can use the specific heat capacity of water and the formula for heat:
Q = m × c × ΔT
where Q is the heat, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
The specific heat capacity of water is approximately 4.184 J/g°C.
To find ΔT, we need to subtract the final temperature (0ºC) from the initial temperature (80ºC):
ΔT = 0°C - 80°C = -80°C
Note that we use -80°C instead of 80°C in the formula, because we are calculating the amount of heat that needs to be removed from the water.
Now we can plug in the values and calculate the heat:
Q = 600 g × 4.184 J/g°C × (-80°C)
Q = -201,216 J
Since the heat is being removed from the water, the value for Q is negative, indicating that the process is exothermic.
Therefore, the amount of heat that must be removed from 600 g of water at 80ºC to bring it down to 0ºC is 201,216 J.