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100 points G.GPE.4 ■ Use coordinates to prove simple geometric theorems algebraically;

for example prove or disprove that the point (1, √3) lies on the circle centered at
the origin and containing the point (0, 2).

User Vagran
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6.8k points

1 Answer

6 votes

Given:-

  • A circle is centred at origin .
  • It contains a point (0,2) .

To prove/disprove :-

  • The point (1,√3) lies on the circle.

Answer :-

Here we are given that the circle is centred at origin that is at (0,0) . And it contains a point (0,2) . Using distance formula we can find the radius of the circle. The distance formula is ,


\implies d =√((x_2-x_1)^2+(y_2-y_1)^2)\dots (i)\\

and here,


  • d = r

  • x_1 = 0

  • x_2 = 0

  • y_1 = 0

  • y_2 = 2

on substituting the respective values, in (i) , we have;


\implies r = √( (0-0)^2 + (2-0)^2) \\


\implies r =√( 2^2) \\


\implies r = 2 \ units \\

hence the radius of the circle is 2 units .

Now find the distance of the point (1,√3) from the centre using distance formula and if
d = rthen the point lies on the circle.


\implies d =√( (1-0)^2+(\sqrt3-0)^2)\\


\implies d = √( 1 + 3 ) =√(4) \\


\implies \underline{\underline{ d = 2 \ units}} \\

Hence here ,


\implies d = r \\

So the given point lies on the circle.

and we are done!

User Michael Bellhouse
by
7.9k points