Question

3c^2 - 20c + 12 factorise by splitting the middle

Answer 1

(3c - 2)(c - 6)

Explanation:

Quadratic Formula:

ax^2 + bx + c

a = 3 and c = 12

a * c --> 3 * 12 = 36

b --> -20

Two numbers that multiply to get 36 and added together get -20 are -18 and -2.

-18(-2) = 36

-18 + (-2) = -20

`(-18)/(3c) = (-6)/(c)`,
`(-2)/(3c)`

(c - 6)(3c - 2) = 3c^2 - 20c + 12