Question

Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.

­­2NaClO3­ --> 2NaCl +3O2



How many grams of NaClO3­ were needed to produce 9 grams of O2? Round your answer to the nearest whole number.

Round your answer to the whole number. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Sodium

23

Chlorine

35.5

Copper

63.5

Oxygen

16

Answer 1

5

Step-by-step explanation:

2NaClO3 --> 2NaCl +3O2

The mole ratio of NaClO3 to O2 is 2:3.

Thus, every 3 moles of O2 require 2 moles of NaClO3 .

7 moles of O2 will, therefore require:

= 2 x7/3

= 4.6666 moles of NaClO3

To the nearest whole number = 5 moles of NaClO3

*phew* it's a lot of work huh

Hope this helps :)