Question

I've been stuck on this for 7 minutes please help me ​

Answer 1

P(green or red) = 935/2721

P(blue, red, or yellow) = 409/907

P(not brown) = 2236/2721

P(not green) = 2171/2721

Explanation:

Probability in this problem can be represented by the ratio:

`\frac{\text{part}}{\text{whole}}`

We can apply this to the first question:

The probability of choosing a green or red M&M can be represented with:

`\frac{\# \text{ of red and green M}\& \text{Ms}}{\text{total } \# \text{ of M}\& \text{Ms}}`

(Note: '#' means 'number')

We can fill this ratio in with the values given in the table.

`(385 + 550)/(2721)`

This simplifies to:

`(935)/(2721)`

So, the probability of choosing a green or red M&M is 935/2721.

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We can apply this same concept to the rest of the questions.