Answer:
the solution to the differential equation is:
3y^2 - 12y = x^2 + 6.
Explanation:
We can use the equation 6y dy - 12 dy = 2xy dx to solve this differential equation using separation of variables.
First, we can rearrange the equation as:
(6y - 12)dy = 2xy dx
Next, we can separate the variables:
(6y - 12)dy = 2xy dx
∫ (6y - 12)dy = ∫ 2xy dx
3y^2 - 12y = x^2 + C
where C is the constant of integration.
Now we can use the initial condition to solve for C. Let's say the initial condition is y(0) = 2, then we have:
3(2)^2 - 12(2) = 0 + C
C = 6
Therefore, the solution to the differential equation is:
3y^2 - 12y = x^2 + 6.
This differential equation is not homogeneous or exact.