Answer:
659.95 grams of NaCl are produced from 452.5 grams of NaOH when the reaction is complete.
Step-by-step explanation:
To answer this question, we first need to calculate the number of moles of NaOH present in 452.5 grams of NaOH. We can use the molar mass of NaOH, which is 40.00 g/mol, to do this:
Moles of NaOH = Mass of NaOH / Molar mass of NaOH
Moles of NaOH = 452.5 g / 40.00 g/mol
Moles of NaOH = 11.31 mol
Now we can use the balanced chemical equation to determine the number of moles of NaCl produced when 11.31 moles of NaOH react:
NaOH + BaCl2 → NaCl + Ba(OH)2
According to the equation, 1 mole of NaOH produces 1 mole of NaCl. Therefore, 11.31 moles of NaOH will produce 11.31 moles of NaCl.
Finally, we can convert the number of moles of NaCl to grams using the molar mass of NaCl, which is 58.44 g/mol:
Mass of NaCl = Moles of NaCl x Molar mass of NaCl
Mass of NaCl = 11.31 mol x 58.44 g/mol
Mass of NaCl = 659.95 g