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Ted made a nut mixture that contains 52%

peanuts by mixing together 9 kg of mixed
nuts that contain 20% peanuts and 16 kg
of a different brand of mixed nuts. The
second brand of mixed nuts contained
what percent peanuts?

User Somejkuser
by
8.2k points

1 Answer

4 votes

Let's call the added amount of kg of mixed nuts that contain

40

%

peanuts

m

a

d

d

e

d

. If the new mixture contains

34

%

peanuts, then:

m

peanuts

m

total

=

0.34

The bag of

6

kg

already contained

0.3

6

=

1.8

kg

of peanuts. Furthermore,

40

%

of

m

added

will be peanuts. This means that:

m

peanuts

=

0.4

m

added

+

1.8

The total mass will be the original

6

kg

plus the added mass, so

m

total

=

m

added

+

6

.

This gives us the following equation.

0.4

m

added

+

1.8

m

added

+

6

=

0.34

Multiply both sides with

m

added

+

6

.

0.4

m

added

+

1.8

=

0.34

(

m

added

+

6

)

Multiply out the brackets.

0.4

m

added

+

1.8

=

0.34

m

added

+

2.04

Subtract

0.34

m

added

from both sides.

0.04

m

added

+

1.8

=

2.04

Subtract

1.8

from both sides.

0.06

m

added

=

0.24

Divide both sides by

0.06

.

m

added

=

4

Therefore, Jenny must add

4

kg

.

User Gyuri Majercsik
by
8.6k points