Question

An open manometer is filled with mercury and

connected to a container of hydrogen. The
mercury level is 78.0 mm higher in the arm of the
tube connected to the air. Air pressure is
100.7 kPa. What is the pressure of the hydrogen in kilopascals?

Does anyone know what the container pressure would be? and how do I solve this?

Answer 1

The pressure of the hydrogen in the container can be determined by using the equation:

P_H2 + ρgh = P_air

where P_H2 is the pressure of the hydrogen, ρ is the density of mercury (13,600 kg/m^3), g is the acceleration due to gravity (9.8 m/s^2), and h is the height difference between the mercury levels in the two arms of the manometer.

First, we need to convert the height difference from millimeters to meters:

h = 78.0 mm = 0.078 m

Next, we can substitute the given values into the equation:

P_H2 + (13,600 kg/m^3)(9.8 m/s^2)(0.078 m) = 100.7 kPa

Solving for P_H2, we get:

P_H2 = 100.7 kPa - (13,600 kg/m^3)(9.8 m/s^2)(0.078 m)

P_H2 = 99.0 kPa

Therefore, the pressure of the hydrogen in the container is 99.0 kPa