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The sum of 3 consecutive multiples of 8 is 888 find the multiples

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5 votes

Answer:


\fbox{\textbf{288, 296, and 304}}</p><p>

Explanation:

Let's assume the first multiple of 8 is x, then the second multiple is x+8, and the third multiple is x+16.

According to the problem statement, the sum of these three multiples is 888:

x + (x+8) + (x+16) = 888

Simplifying the left side:

3x + 24 = 888

Subtracting 24 from both sides:

3x = 864

Dividing both sides by 3:

x = 288

Therefore, the first multiple of 8 is 288, the second is x+8 = 296, and the third is x+16 = 304.

So, the three consecutive multiples of 8 that add up to 888 are 288, 296, and 304

User Efe Kahraman
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