Question

I need help solve for X and Y

Answer 1

x=7
`√(3)`, y=14

Explanation:

Since it's a right triangle, and we know the degree is 30, so

7=sin30·y,

y=
`(7)/(sin30)`=14,

`x^(2)`+
`7^(2)`=
`y^(2)`.

x=
`\sqrt{14^(2)-7^(2) }`=
`√(147 )`=7
`√(3)`

Answer 2

x = 7
`√(3)` , y = 14

Explanation:

using the tangent and sine ratios in the right triangle and the exact values

tan30° =
`(1)/(√(3) )` and sin30° =
`(1)/(2)` , then

tan30° =
`(opposite)/(adjacent)` =
`(7)/(x)` =
`(1)/(√(3) )` ( cross- multiply )

x = 7
`√(3)`

and

sin30° =
`(opposite)/(hypotenuse)` =
`(7)/(y)` =
`(1)/(2)` ( cross- multiply )

y = 14