Answer:
the correct responses are:
The graph will have a vertical asymptote at x = π/2.
The graph will have a vertical asymptote at x = 3π/2.
The graph will have a vertical asymptote at x = 2π.
The graph will not go through the point (π/4, 1).
Explanation:
The statements that are true about the graph of f(x) = cot(x) are:
The graph will have a vertical asymptote at x = π/2.
The graph will have a vertical asymptote at x = 3π/2.
The graph will have a vertical asymptote at x = 2π.
These are true because the cotangent function has vertical asymptotes at every odd multiple of π/2, which includes π/2, 3π/2, and 5π/2, and so on.
The statement that the graph will go through the point (π/4, 1) is false. The cotangent function does not pass through this point, although it does have a vertical asymptote at x = π/4.
Therefore, the correct responses are:
The graph will have a vertical asymptote at x = π/2.
The graph will have a vertical asymptote at x = 3π/2.
The graph will have a vertical asymptote at x = 2π.
The graph will not go through the point (π/4, 1).